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In write a c program to check whether a character is alphabet or not. (A-Z or a-z) is a fundamental concept. This is particularly useful in input validation, text processing, and various algorithmic implementations. The C programming language provides a straightforward approach to solving this problem using conditional statements.
Understanding the Problem
A character is considered an alphabet if it falls within the following ASCII ranges:
Uppercase letters: ASCII values from 65 ('A') to 90 ('Z')
Lowercase letters: ASCII values from 97 ('a') to 122 ('z')
Any character outside these ranges, such as digits (0-9) and special symbols (@, #, *, etc.), is not considered an alphabet.
Approach to the Solution
We can determine if a given character is an alphabet using:
Conditional Statements (if-else): Comparing the ASCII values of the character.
Library Functions: The library provides the isalpha() function, which can check if a character is an alphabet.
C Program Using if-else Statement
c
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#include
int main() {
char ch;
// Input from user
printf("Enter a character: ");
scanf("%c", &ch);
// Check if character is an alphabet
if ((ch >= 'A' && ch = 'a' && ch
#include
int main() {
char ch;
// Input from user
printf("Enter a character: ");
scanf("%c", &ch);
// Using isalpha() function
if (isalpha(ch)) {
printf("'%c' is an alphabet.\n", ch);
} else {
printf("'%c' is not an alphabet.\n", ch);
}
return 0;
}
Why Use isalpha()?
The isalpha() function from simplifies the check.
It enhances code readability and ensures efficiency.
Output Examples
Example 1:
pgsql
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Enter a character: G
'G' is an alphabet.
Example 2:
pgsql
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Enter a character: 5
'5' is not an alphabet.
Conclusion
This program effectively checks whether a character is an alphabet or not using both manual conditions and the isalpha() function. The approach ensures accuracy while maintaining simplicity, making it suitable for beginner-level programming tasks.
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